Multiplication of two numbers ending with 5 difference of 20

#Multiplication of two numbers ending with 5 difference of  20

Rule :- p5  ×(p+2) 5 = ((p+2)^2 -(p+3 )) /25

Consider For example :-
       25×45 =??
           Here  ( p+2)^2
                     =4^2
                      =16.
Here p+3 =5
       Therefore, 25×45 =(4^2 -5 )/25
                                          = ( 16-5)/25
                                          =11/25
      Therefore,  25×45=1125.

Let’s take one more example:-

     55×75 =??
       55×75 =(7^2 -8)/25
                   =(49-8 )/25
                     =4125

It is simple 🙂

Thank you for your help and support. You can find me on Facebook , Google+

Posted by Praveenkumar P K

Advertisements

About Praveenkumar P Kalikeri

ABOUT US Hey,Thanks for dropping by .First I would like to Appreciate for your love towards the Mathematics Subject. My name is Praveenkumar Kalikeri. I'm an Engineering Student from Karnataka , India. My Passion for Mathematics , encouraged me to start this blog . I Started loving the Mathematics subject from my schooling days.I was greatly motivated by teachers, parents who always helped me .        Numbers have Beauty !! They fascinated me .. As we all know best method to try out something new is to study old theories , concepts , its drawbacks, etc. I ,myself Started learning Vedic Mathematics at age of 15. Here , I will share vedic maths tricks learned and modified by me in simple manner which will be useful in various competitive exams. "If You Believe , You Can Do".
This entry was posted in vedic Mathematics and tagged , , . Bookmark the permalink.