__Squaring of Number Consisting of only 3’s__

__ Rule:__– Write the 0 and 9 with one minus the no of the 3’s given.Then to left of 0 increment it by 1. To left of 0 write two 8’s.

** ( p-1) no of 1’s / 0 /(p-1) no of 8’s /9**

** Lets look at the following examples:-**

__Example 1:__–

** 333^2 =**

** Here p=3**

** Therefore, 333^2 =**

** = (3-1) no of 1’s / 0/(3-1) no of 8’s /9**

** = 11/0/88/9**

__Example 2:__–

** 33^2 =**

** Here p=2**

** 1/0/8/9**

** Therefore, 33^2 =1089.**

__Example3:__ –

** 33333^2 =**

** Looks like it is difficult ?**

** Here we go with same logic….**

** p=5 **

** Therefore, (1111) /0/(8888)/9**

** 33333^2 =1111088889**

**That’s impressive , isn’t it **

**Pattern **

**Recognition**

** **

** **

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Posted by Praveenkumar P K

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## About Praveenkumar P Kalikeri

ABOUT US
Hey,Thanks for dropping by .First I would like to Appreciate for your love towards the Mathematics Subject.
My name is Praveenkumar Kalikeri.
I'm an Engineering Student from Karnataka , India.
My Passion for Mathematics , encouraged me to start this blog .
I Started loving the Mathematics subject from my schooling days.I was greatly motivated by teachers, parents who always helped me .
Numbers have Beauty !!
They fascinated me ..
As we all know best method to try out something new is to study old theories , concepts , its drawbacks, etc.
I ,myself Started learning Vedic Mathematics at age of 15.
Here , I will share vedic maths tricks learned and modified by me in simple manner which will be useful in various competitive exams.
"If You Believe , You Can Do".